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Question #42386

Difficulty: 8/10 | 🟢 Free

The Question

A diatomic molecule is modeled as a rigid massless rod of length LL with two point masses: m1=mm_1 = m with charge +q+q, and m2=2mm_2 = 2m with charge −q-q. The molecule lies on a smooth horizontal insulating table inside a box. Mass m1m_1 is hinged to the floor of the box. A uniform electric field E⃗=Ei^\vec{E} = E \hat{i} exists throughout the space. The box is given a constant horizontal acceleration a⃗=ai^\vec{a} = a \hat{i}. Initially, the rod is held at rest (relative to the box) parallel to the positive yy-axis. It is then released. Find the magnitude of the force exerted by the hinge on m1m_1 in the xx-direction at the instant the rod aligns with the negative xx-axis.

Options

  • A.

    2qE+7ma2qE + 7ma

  • B.

    3qE+6ma3qE + 6ma

  • C.

    2qE+3ma2qE + 3ma

  • D.

    2qE2qE

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Work-Energy Theorem for Rotation|Reduced Mass Effect|Vector Cross-Product

Why This Question Is Tricky

Common Mistakes

This problem tests the application of the work-energy theorem and circular motion dynamics in a non-inertial frame.

A common trap is ignoring the work done by the pseudo-force on the rotating mass, as students often mistakenly assume pseudo-forces only affect translational equilibrium.

Additionally, students may forget to include the pseudo-force on the hinged mass when calculating the final hinge reaction, or incorrectly identify the tension in the rod as the total hinge force.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSystem of Particles and Rotational Motion - Class 11 Part 1
ConceptWork-Energy Theorem for Rotation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree