Start Learning Free

Before You Begin

Question #42364

Difficulty: 8/10 | 🟢 Free

The Question

A uniform horizontal circular disc of mass MM (in kg) and radius RR (in m) is suspended by a vertical wire of torsional constant KK (in N⋅\cdotm/rad). Initially, it is undergoing torsional oscillations. At time t=0t=0 (in s), the disc passes through its mean position (angular displacement θ=0\theta = 0 rad) with angular velocity ω0\omega_0 (in rad/s). From t=0t=0 onwards, sand falls vertically onto the edge of the disc at a constant rate μ=dmdt\mu = \frac{dm}{dt} (in kg/s) and sticks to it. Assuming the sand has no initial horizontal velocity, which of the following expressions gives the angular acceleration α\alpha (in rad/s2^2) of the disc at any time t>0t > 0 in terms of its instantaneous angular displacement θ\theta and angular velocity ω\omega?

Options

  • A.

    −Kθ+μR2ω12MR2+μR2t-\frac{K\theta + \mu R^2 \omega}{\frac{1}{2}MR^2 + \mu R^2 t}

  • B.

    −Kθ12MR2+μR2t-\frac{K\theta}{\frac{1}{2}MR^2 + \mu R^2 t}

  • C.

    −Kθ−μR2ω12MR2+μR2t-\frac{K\theta - \mu R^2 \omega}{\frac{1}{2}MR^2 + \mu R^2 t}

  • D.

    −Kθ+12μR2ω12MR2+μR2t-\frac{K\theta + \frac{1}{2}\mu R^2 \omega}{\frac{1}{2}MR^2 + \mu R^2 t}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Variable Mass Systems|Angular Momentum conservation|Torsional Oscillations

Why This Question Is Tricky

Common Mistakes

This question tests the application of Newton's Second Law for rotation in variable mass systems.

A common trap is assuming τ=Iα\tau = I\alpha holds universally, leading students to incorrectly write −Kθ=I(t)α-K\theta = I(t)\alpha.

However, when mass is added at a rate μ\mu, the correct formulation is τext=dL/dt=Iα+ω(dI/dt)\tau_{ext} = dL/dt = I\alpha + \omega(dI/dt).

The incoming mass must be accelerated to the tangential velocity of the disc, which exerts a dynamic braking torque −ω(dI/dt)-\omega(dI/dt) on the system.

This manifests as a velocity-dependent damping term in the torsional oscillator's differential equation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSystem of Particles and Rotational Motion - Class 11 Part 1
ConceptVariable Mass Systems
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree