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Question #42364
The Question
A uniform horizontal circular disc of mass (in kg) and radius (in m) is suspended by a vertical wire of torsional constant (in Nm/rad). Initially, it is undergoing torsional oscillations. At time (in s), the disc passes through its mean position (angular displacement rad) with angular velocity (in rad/s). From onwards, sand falls vertically onto the edge of the disc at a constant rate (in kg/s) and sticks to it. Assuming the sand has no initial horizontal velocity, which of the following expressions gives the angular acceleration (in rad/s) of the disc at any time in terms of its instantaneous angular displacement and angular velocity ?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Variable Mass Systems|Angular Momentum conservation|Torsional Oscillations
Why This Question Is Tricky
Common Mistakes
This question tests the application of Newton's Second Law for rotation in variable mass systems.
A common trap is assuming holds universally, leading students to incorrectly write .
However, when mass is added at a rate , the correct formulation is .
The incoming mass must be accelerated to the tangential velocity of the disc, which exerts a dynamic braking torque on the system.
This manifests as a velocity-dependent damping term in the torsional oscillator's differential equation.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | System of Particles and Rotational Motion - Class 11 Part 1 |
| Concept | Variable Mass Systems |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |