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Question #42355

Difficulty: 8/10 | 🟢 Free

The Question

A microscopic cavity contains NN molecules of an ideal rigid diatomic gas, each of mass mm. The cavity is driven by an external mechanism to oscillate along the xx-axis with a velocity v(t)=V0cos⁡(ωt)v(t) = V_0 \cos(\omega t). The frequency ω\omega is sufficiently high such that the center of mass of the gas oscillates synchronously with the cavity. In a dynamic steady state, the time-averaged total kinetic energy of the gas (including both translational and rotational motion) measured in the stationary laboratory frame is EE. Which of the following expressions gives the true thermodynamic temperature TT of the gas? (Here kBk_B is the Boltzmann constant).

Options

  • A.

    4E−NmV0210NkB\frac{4E - N m V_0^2}{10 N k_B}

  • B.

    2E5NkB\frac{2E}{5 N k_B}

  • C.

    4E+NmV0210NkB\frac{4E + N m V_0^2}{10 N k_B}

  • D.

    4E−NmV026NkB\frac{4E - N m V_0^2}{6 N k_B}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Center of Mass (COM) Frame|Energy of Vibrational Modes|Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to distinguish between the macroscopic bulk kinetic energy of a system and its microscopic internal energy (thermal energy) in a non-inertial, oscillating reference frame.

A common trap is to equate the total time-averaged kinetic energy measured in the lab frame directly to the internal energy (E=52NkBTE = \frac{5}{2} N k_B T), implicitly treating the cavity as a static boundary.

By forcing the transition from the lab frame to the center-of-mass frame, students must correctly apply the kinetic energy decomposition theorem (Klab=Kcom+KinternalK_{lab} = K_{com} + K_{internal}) and compute the time-averaged bulk kinetic energy (14NmV02\frac{1}{4} N m V_0^2) to isolate the true thermodynamic temperature.

An additional trap is using the incorrect degrees of freedom for a diatomic gas.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSystem of Particles and Rotational Motion - Class 11 Part 1
ConceptCenter of Mass (COM) Frame
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree