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Question #42349
The Question
A uniform conducting rod of length and resistance rotates with a constant angular velocity about one of its ends in a uniform magnetic field directed perpendicular to the plane of rotation. The free end of the rod slides on a fixed, frictionless, perfectly conducting circular ring. A stationary resistor of resistance is connected between the pivot and the ring. If the rod completes one full revolution, what is the work done by the magnetic force on the charge carriers, and the work done by the external mechanical agent to maintain the constant angular velocity, respectively?
Options
- A.
and
- B.
and
- C.
and
- D.
and
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Conservative vs Non-conservative|Work-Energy Theorem for Rotation|Motional EMF in Rotating Rods
Why This Question Is Tricky
Common Mistakes
This question tests the fundamental misconception that the magnetic force does work to drive the induced current in a motional EMF setup.
Students frequently calculate the Joule heating energy and incorrectly attribute it to the work done by the magnetic field.
In reality, the Lorentz force on a moving charge is always perpendicular to its velocity, meaning the magnetic field does zero work.
The electrical energy dissipated in the resistors comes entirely from the mechanical work done by the external agent against the macroscopic magnetic drag (Laplace force), highlighting the non-conservative nature of the induced electric field and the proper application of the Work-Energy Theorem for rotating systems.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Work, Energy, and Power - Class 11 Part 1 |
| Concept | Conservative vs Non-conservative |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |