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Question #42326

Difficulty: 8/10 | 🟢 Free

The Question

A thin cylindrical rod of length LL and uniform cross-sectional area AA has a non-uniform density given by ρ(x)=ρ0(1+xL)\rho(x) = \rho_0 \left(1 + \frac{x}{L}\right), where xx is the distance from one end (x=0x=0). The rod is completely submerged in a large tank of ideal liquid of uniform density ρ0\rho_0. The rod is initially held at rest in a horizontal position at a sufficient depth and then released. Assuming viscous drag is negligible, find the angular velocity ω\omega of the rod when it reaches the vertical position for the first time.

Options

  • A.

    12g13L\sqrt{\frac{12g}{13L}}

  • B.

    8g9L\sqrt{\frac{8g}{9L}}

  • C.

    4g3L\sqrt{\frac{4g}{3L}}

  • D.

    6g13L\sqrt{\frac{6g}{13L}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Mechanical Energy Conservation|Archimedes' Buoyancy Dynamics|Integration

Why This Question Is Tricky

Common Mistakes

Students often incorrectly assume the rod rotates about its geometric center or one of its ends, failing to decouple the translational and rotational dynamics.

Furthermore, they frequently misidentify the work done by the buoyant force, treating it as a non-conservative force or failing to recognize that in the CM frame, the pseudo-forces do zero work, leaving buoyancy as the sole contributor to rotational kinetic energy.

This question rigorously tests the application of the work-energy theorem in an accelerating non-inertial frame and the distinction between the center of mass and center of buoyancy in non-uniform bodies.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWork, Energy, and Power - Class 11 Part 1
ConceptMechanical Energy Conservation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree