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Question #42306

Difficulty: 8/10 | 🟢 Free

The Question

A long straight wire carrying a steady current II lies along the zz-axis. A curved open surface SS is defined by the parabolic equation y=x2ay = \frac{x^2}{a} for the range a≤x≤2aa \le x \le 2a, and is bounded in the zz-direction by 0≤z≤L0 \le z \le L. Calculate the magnitude of the magnetic flux through this surface SS.

Options

  • A.

    μ0IL4πln⁡10\frac{\mu_0 I L}{4\pi} \ln 10

  • B.

    μ0IL4πln⁡(2.5)\frac{\mu_0 I L}{4\pi} \ln(2.5)

  • C.

    μ0IL4πln⁡(1.6)\frac{\mu_0 I L}{4\pi} \ln(1.6)

  • D.

    μ0IL2πln⁡2\frac{\mu_0 I L}{2\pi} \ln 2

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Dot Product Geometry|Ampere’s Circuital Law Symmetry

Why This Question Is Tricky

Common Mistakes

This question tests a lethal trap in vector calculus applied to electromagnetism: incorrectly simplifying the surface integral of the magnetic flux by projecting a curved surface onto a single coordinate plane.

In a non-uniform field where the angle between B⃗\vec{B} and dA⃗d\vec{A} varies continuously, students often mistakenly calculate only ∫BxdAx\int B_x dA_x or ∫BydAy\int B_y dA_y, which leads directly to the distractors ln⁡(2.5)\ln(2.5) or ln⁡(1.6)\ln(1.6).

Another common error is ignoring the surface geometry entirely and treating it as a flat radial plane, leading to the ln⁡2\ln 2 distractor.

The rigorous approach requires parameterizing the surface to find the exact dA⃗d\vec{A} vector and evaluating the full dot product.

Alternatively, top-tier students can bypass the trap entirely by using the magnetic vector potential A⃗=−μ0I2πln⁡rk^\vec{A} = -\frac{\mu_0 I}{2\pi} \ln r \hat{k} and applying Stokes' Theorem to evaluate the flux as a simple line integral along the boundaries.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWork, Energy, and Power - Class 11 Part 1
ConceptDot Product Geometry
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree