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Question #42271

Difficulty: 8/10 | 🟢 Free

The Question

A planet of mass MM and cross-sectional area ApA_p is in a nearly circular orbit of radius RR around a star of mass MsM_s. The star emits a steady, spherically symmetric stellar wind of gas radially outwards at a constant speed vwv_w. The total mass loss rate of the star due to this wind is m˙\dot{m}. The planet experiences a tangential drag force of magnitude FD=CdρApv2F_D = C_d \rho A_p v^2, where ρ\rho is the local gas density, vv is the planet's orbital speed, and CdC_d is the drag coefficient. Assuming M≪MsM \ll M_s and vw≪vv_w \ll v, what is the magnitude of the rate of change of the planet's areal velocity, ∣dVAdt∣\left| \frac{dV_A}{dt} \right|?

Options

  • A.

    Cdm˙ApGMs8πMR2vw\frac{C_d \dot{m} A_p G M_s}{8\pi M R^2 v_w}

  • B.

    Cdm˙ApGMs4πMR2vw\frac{C_d \dot{m} A_p G M_s}{4\pi M R^2 v_w}

  • C.

    Cdm˙ApGMs2πMR2vw\frac{C_d \dot{m} A_p G M_s}{2\pi M R^2 v_w}

  • D.

    Cdm˙ApGMs16πMR2vw\frac{C_d \dot{m} A_p G M_s}{16\pi M R^2 v_w}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Kepler’s Second Law (Areal Velocity)|Equation of Continuity|Small Angle Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of fluid continuity, orbital mechanics, and non-conservative forces.

A common trap is assuming Kepler's Second Law (constant areal velocity) holds universally, ignoring that drag provides a tangential torque.

Students may also incorrectly attempt to use energy conservation to find the orbital decay, which complicates the extraction of angular momentum loss.

Furthermore, the presence of the star's variable mass (m˙\dot{m}) acts as a conceptual decoy; while it causes the orbit to expand (MsR=constM_s R = \text{const}), central mass loss exerts no torque and thus does not affect the areal velocity.

The only source of areal velocity decay is the drag torque, requiring the correct application of VA=L/2MV_A = L/2M and the continuity equation ρ=m˙/(4πR2vw)\rho = \dot{m}/(4\pi R^2 v_w).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterGravitation - Class 11 Part 1
ConceptKepler’s Second Law (Areal Velocity)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree