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Question #42271
The Question
A planet of mass and cross-sectional area is in a nearly circular orbit of radius around a star of mass . The star emits a steady, spherically symmetric stellar wind of gas radially outwards at a constant speed . The total mass loss rate of the star due to this wind is . The planet experiences a tangential drag force of magnitude , where is the local gas density, is the planet's orbital speed, and is the drag coefficient. Assuming and , what is the magnitude of the rate of change of the planet's areal velocity, ?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Kepler’s Second Law (Areal Velocity)|Equation of Continuity|Small Angle Approximation
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of fluid continuity, orbital mechanics, and non-conservative forces.
A common trap is assuming Kepler's Second Law (constant areal velocity) holds universally, ignoring that drag provides a tangential torque.
Students may also incorrectly attempt to use energy conservation to find the orbital decay, which complicates the extraction of angular momentum loss.
Furthermore, the presence of the star's variable mass () acts as a conceptual decoy; while it causes the orbit to expand (), central mass loss exerts no torque and thus does not affect the areal velocity.
The only source of areal velocity decay is the drag torque, requiring the correct application of and the continuity equation .
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Gravitation - Class 11 Part 1 |
| Concept | Kepler’s Second Law (Areal Velocity) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |