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Question #42192

Difficulty: 8/10 | 🟢 Free

The Question

A thermally insulated cylinder with a movable piston contains a solid semiconductor sample of constant heat capacity Cs=4RC_s = 4R and a gas mixture in thermal equilibrium at an initial temperature T0T_0. The gas mixture consists of a total of 44 moles of Helium (He) and Oxygen (O2\text{O}_2). According to Dalton's law of partial pressures, the initial partial pressure of He is equal to the partial pressure of O2\text{O}_2. The system undergoes a reversible adiabatic expansion from an initial volume V0V_0 to a final volume 8V08V_0. The intrinsic carrier concentration of the semiconductor is given by ni(T)=AT3/2e−Eg/2kBTn_i(T) = A T^{3/2} e^{-E_g / 2k_B T}, where the band gap energy is Eg=4kBT0E_g = 4 k_B T_0. Assuming the volume of the semiconductor is negligible, what is the ratio of the final intrinsic carrier concentration to the initial intrinsic carrier concentration, ni(Tf)ni(T0)\frac{n_i(T_f)}{n_i(T_0)}?

Options

  • A.

    122e2\frac{1}{2\sqrt{2} e^2}

  • B.

    122e4\frac{1}{2\sqrt{2} e^4}

  • C.

    1e2\frac{1}{e^2}

  • D.

    8−3/4e2−428^{-3/4} e^{2-4\sqrt{2}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Adiabatic Process Constraint|Dalton's Law of Partial Pressures|Energy Band Gap Temperature Dependency

Why This Question Is Tricky

Common Mistakes

This question tests the application of the First Law of Thermodynamics to a composite system (gas mixture + solid) undergoing an adiabatic process.

The primary trap is treating the semiconductor as a passive object and ignoring its heat capacity (CsC_s), which leads to an incorrect effective adiabatic exponent and a wrong final temperature (Option D).

It also integrates solid-state physics by requiring the evaluation of the intrinsic carrier concentration's temperature dependence, testing if students correctly apply the T3/2T^{3/2} pre-exponential factor and the Boltzmann factor e−Eg/2kBTe^{-E_g/2k_BT} (Options B and C represent common formulaic errors).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermodynamics - Class 11 Part 2
ConceptAdiabatic Process Constraint
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree