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Question #42180

Difficulty: 8/10 | 🟢 Free

The Question

One mole of an ideal monatomic gas is confined in a cylinder by a movable piston of area AA. The piston contains a magnetic core of volume VpV_p. The system is placed in an external magnetic field B=kxi^\mathbf{B} = kx \hat{i}, where xx is the position of the piston. The gas undergoes a cyclic process consisting of four steps:

  1. Isobaric expansion at pressure P0P_0 from x1x_1 to x2x_2. The core's magnetization is constant at M0i^M_0 \hat{i}.
  2. Isochoric depressurization to P0/2P_0/2. The magnetization changes to 3M0i^3M_0 \hat{i}.
  3. Isobaric compression at P0/2P_0/2 back to x1x_1. The magnetization is constant at 3M0i^3M_0 \hat{i}.
  4. Isochoric pressurization to P0P_0. The magnetization returns to M0i^M_0 \hat{i}. Let ΔV=A(x2−x1)\Delta V = A(x_2 - x_1) and define a dimensionless parameter β=VpM0kP0A\beta = \frac{V_p M_0 k}{P_0 A}. Which of the following gives the effective molar heat capacity CeffC_{eff} of the system during the isobaric expansion (step 1), and the net heat QnetQ_{net} absorbed by the system over one complete cycle?

Options

  • A.

    Ceff=R(52+β),Qnet=P0ΔV(12−2β)C_{eff} = R\left(\frac{5}{2} + \beta\right), \quad Q_{net} = P_0 \Delta V \left(\frac{1}{2} - 2\beta\right)

  • B.

    Ceff=52R,Qnet=P0ΔV(12+2β)C_{eff} = \frac{5}{2}R, \quad Q_{net} = P_0 \Delta V \left(\frac{1}{2} + 2\beta\right)

  • C.

    Ceff=R(52−β),Qnet=P0ΔV(12−2β)C_{eff} = R\left(\frac{5}{2} - \beta\right), \quad Q_{net} = P_0 \Delta V \left(\frac{1}{2} - 2\beta\right)

  • D.

    Ceff=R(52+β),Qnet=P0ΔV(12+2β)C_{eff} = R\left(\frac{5}{2} + \beta\right), \quad Q_{net} = P_0 \Delta V \left(\frac{1}{2} + 2\beta\right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Molar Heat Capacity (Cv vs Cp)|Hysteresis Loop Area|Force on Current-Carrying Loop

Why This Question Is Tricky

Common Mistakes

This question tests the generalized First Law of Thermodynamics dU=dQ−dWnetdU = dQ - dW_{net}, where the total work includes both PV work and magnetic work.

The magnetic force on the piston Fm=mdBdxF_m = m \frac{dB}{dx} acts in the direction of expansion, modifying the effective pressure and thus altering the molar heat capacity CeffC_{eff} from the standard Cp=52RC_p = \frac{5}{2}R.

Furthermore, the magnetic cycle traces a hysteresis loop.

The magnetic work done by the system over the cycle is proportional to ∮M dV\oint M \, dV, which is negative, representing hysteresis energy loss (work done ON the system).

Students often fall into the trap of either ignoring this non-PV work in CeffC_{eff} or incorrectly adding the hysteresis loss to the net heat absorbed, failing to realize that dissipation reduces the net work output and thus the net heat absorbed in a cycle.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermodynamics - Class 11 Part 2
ConceptMolar Heat Capacity (Cv vs Cp)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree