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Question #42149
The Question
A heating coil of resistance and inductance is immersed in a calorimeter of heat capacity . At , the coil is connected to an ideal DC voltage source . The calorimeter loses heat to the surroundings (at constant temperature ) at a rate , where is the instantaneous temperature of the calorimeter and is a positive constant. Assume the electrical time constant of the coil is exactly equal to the thermal time constant of the calorimeter, i.e., . If the initial temperature of the calorimeter is , which of the following expressions correctly gives the temperature difference at any time ?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Calorimetry with Heat Loss|Transient Current in RL Circuit|Work, Energy, and Power
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of transient electrical circuits and non-steady-state calorimetry.
The lethal trap lies in the non-linear coupling of the transient current to the thermal power ().
Students often incorrectly assume the power grows linearly with the current transient, leading to (Option C), or they completely ignore the transient phase and assume steady-state power from (Option B).
By equating the electrical and thermal time constants, the problem forces the resolution of a first-order non-homogeneous differential equation with a resonant-like forcing term, rigorously testing the ability to set up and integrate coupled physical rate equations without falling for algebraic shortcuts.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Thermal Properties of Matter - Class 11 Part 2 |
| Concept | Calorimetry with Heat Loss |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |