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Question #42118

Difficulty: 8/10 | 🟢 Free

The Question

A solid sphere of radius rr and uniform density ρ\rho is released from rest at the surface (y=0y=0) of a liquid column. The liquid has a depth-dependent density σ(y)=σ0(1+βy)\sigma(y) = \sigma_0(1 + \beta y) (where ρ>σ0\rho > \sigma_0) and a depth-dependent viscosity η(y)=η0(1+αy)\eta(y) = \eta_0(1 + \alpha y). The sphere is observed to have a velocity vv at a depth y=Hy=H. Which of the following expressions gives the magnitude of the work done by the viscous drag force on the sphere during its descent to depth HH?

Options

  • A.

    43πr3[gH(ρ−σ0)−12gσ0βH2−12ρv2]\frac{4}{3}\pi r^3 \left[ gH(\rho - \sigma_0) - \frac{1}{2}g\sigma_0\beta H^2 - \frac{1}{2}\rho v^2 \right]

  • B.

    43πr3[gH(ρ−σ0)+12gσ0βH2−12ρv2]\frac{4}{3}\pi r^3 \left[ gH(\rho - \sigma_0) + \frac{1}{2}g\sigma_0\beta H^2 - \frac{1}{2}\rho v^2 \right]

  • C.

    6πη0rvH(1+αH2)6\pi\eta_0 r v H \left( 1 + \frac{\alpha H}{2} \right)

  • D.

    43πr3[gH(ρ−σ0)−12ρv2]−3πη0rvH2α\frac{4}{3}\pi r^3 \left[ gH(\rho - \sigma_0) - \frac{1}{2}\rho v^2 \right] - 3\pi\eta_0 r v H^2 \alpha

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Viscosity and Stokes' Law|Work-Energy Theorem Validity|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to recognize when to apply the Work-Energy Theorem instead of attempting to solve an intractable differential equation.

The primary trap is the depth-dependent viscosity η(y)\eta(y), which tempts students to integrate the Stokes' drag force directly as ∫6πη(y)rv dy\int 6\pi\eta(y)rv \, dy.

However, since the velocity profile v(y)v(y) is unknown and terminal velocity is never reached, this integral cannot be evaluated directly.

By applying the Work-Energy Theorem, the non-conservative work done by the drag force can be found purely through the changes in kinetic energy and the work done by the conservative (gravity) and position-dependent (buoyancy) forces, rendering the complex viscosity function a deliberate distractor.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMechanical Properties of Fluids - Class 11 Part 2
ConceptViscosity and Stokes' Law
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree