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Question #42106

Difficulty: 8/10 | 🟢 Free

The Question

A solid sphere of radius RR and density ρs\rho_s falls from rest under gravity in a fluid of density ρf\rho_f and viscosity η\eta. Due to strong molecular cohesion, the fluid does not obey Stokes' law. Instead, a boundary layer of thickness δ\delta forms around the sphere, where δ=R(v0v)\delta = R \left(\frac{v_0}{v}\right), with vv being the instantaneous velocity of the sphere and v0v_0 a characteristic fluid velocity constant. The velocity profile of the fluid within this boundary layer, from the sphere's surface (y=0y=0) to the edge of the layer (y=δy=\delta), is given by u(y)=v(1−yδ)2u(y) = v\left(1 - \frac{y}{\delta}\right)^2. Assuming the drag force is entirely due to the viscous shear stress at the sphere's surface, what is the terminal velocity vTv_T of the sphere?

Options

  • A.

    R(ρs−ρf)gv06ηR \sqrt{\frac{(\rho_s - \rho_f) g v_0}{6 \eta}}

  • B.

    2R2(ρs−ρf)gv09η\sqrt{\frac{2 R^2 (\rho_s - \rho_f) g v_0}{9 \eta}}

  • C.

    R(ρs−ρf)gv03ηR \sqrt{\frac{(\rho_s - \rho_f) g v_0}{3 \eta}}

  • D.

    2R2(ρs−ρf)g9η\frac{2 R^2 (\rho_s - \rho_f) g}{9 \eta}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Molecular Forces of Cohesion|Viscosity and Stokes' Law|Free Body Diagram Isolation|Non-Uniform Acceleration Constraint

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to derive drag force from fundamental fluid dynamics principles rather than blindly applying Stokes' Law (F=6πηRvF = 6\pi\eta R v).

The trap exploits the memorized formula, which is only valid for low Reynolds numbers in homogeneous Newtonian fluids.

By introducing a dynamic boundary layer dependent on a cohesive-to-adhesive velocity ratio, the drag force becomes proportional to v2v^2.

Students who ignore the boundary layer velocity gradient (du/dydu/dy) and default to the standard terminal velocity formula will incorrectly choose Option D.

Those who use an average gradient (v/δv/\delta) instead of the exact surface derivative will miss a factor of 2 and fall for Option C.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMechanical Properties of Fluids - Class 11 Part 2
ConceptMolecular Forces of Cohesion
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree