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Question #42065

Difficulty: 8/10 | 🟢 Free

The Question

A rigid conducting rod OPOP of length LL rotates with a constant angular velocity ω⃗=ωk^\vec{\omega} = \omega \hat{k} about the origin OO in the xyxy-plane. The region contains a static, non-uniform magnetic field given by: B⃗=B0[sin⁡(πxL)cosh⁡(πyL)i^−cos⁡(πxL)sinh⁡(πyL)j^+(x2+y2L2)k^]\vec{B} = B_0 \left[ \sin\left(\frac{\pi x}{L}\right) \cosh\left(\frac{\pi y}{L}\right) \hat{i} - \cos\left(\frac{\pi x}{L}\right) \sinh\left(\frac{\pi y}{L}\right) \hat{j} + \left(\frac{x^2 + y^2}{L^2}\right) \hat{k} \right] An observer O′O' moves with a constant velocity v⃗0=ωLi^+ωLj^\vec{v}_0 = \omega L \hat{i} + \omega L \hat{j} relative to the laboratory frame. What is the magnitude of the motional electromotive force (EMF) across the rod OPOP as measured by the observer O′O'?

Options

  • A.

    14B0ωL2\frac{1}{4} B_0 \omega L^2

  • B.

    13B0ωL2\frac{1}{3} B_0 \omega L^2

  • C.

    12B0ωL2\frac{1}{2} B_0 \omega L^2

  • D.

    54B0ωL2\frac{5}{4} B_0 \omega L^2

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Relative Velocity in 2D|Motional EMF in Rotating Rods|Vector Calculus

Why This Question Is Tricky

Common Mistakes

This question tests two lethal traps in electromagnetic induction.

First, it presents a highly complex, non-uniform magnetic field to bait students into tedious component-wise cross products.

The logical bypass requires recognizing that the scalar triple product (v⃗×B⃗)⋅dl⃗=(dl⃗×v⃗)⋅B⃗(\vec{v} \times \vec{B}) \cdot d\vec{l} = (d\vec{l} \times \vec{v}) \cdot \vec{B} strictly isolates the zz-component of the field, rendering the intimidating in-plane components irrelevant.

Second, it introduces a moving observer to trigger a false relative velocity frame transformation.

Students often incorrectly add a translational EMF term, failing to realize that the total Lorentz force per unit charge (and thus the measured EMF) is invariant under Galilean transformations due to the induced electric field E⃗′=v⃗0×B⃗\vec{E}' = \vec{v}_0 \times \vec{B} in the moving frame.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMotion in a Plane - Class 11 Part 1
ConceptRelative Velocity in 2D
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree