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Question #42057

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass mm is initially at rest at t=0t=0. It is subjected to a time-varying external driving force Fext(t)=ma0e−kmtF_{\text{ext}}(t) = m a_0 e^{-\frac{k}{m}t}, where a0a_0 and kk are positive constants. The particle simultaneously experiences a drag force Fd=−kvF_d = -kv, where vv is its instantaneous velocity. What is the magnitude of the maximum instantaneous power dissipated by the drag force during the motion?

Options

  • A.

    m2a02ke2\frac{m^2 a_0^2}{k e^2}

  • B.

    m2a02k\frac{m^2 a_0^2}{k}

  • C.

    m2a024k\frac{m^2 a_0^2}{4 k}

  • D.

    2m2a02ke\frac{2 m^2 a_0^2}{k e}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Area Under Acceleration-Time|Power-Velocity Relationship|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to couple kinematics with dynamics under time-varying and velocity-dependent forces.

The primary trap lies in treating the external acceleration independently of the drag force.

Students commonly integrate the given acceleration a(t)a(t) directly to find velocity (i.e., v=∫adtv = \int a dt), ignoring that the drag force fundamentally alters the differential equation of motion to dv/dt+(k/m)v=a(t)dv/dt + (k/m)v = a(t).

By setting the external force's decay constant equal to the drag coefficient per unit mass (k/mk/m), the problem requires solving a linear first-order ODE via an integrating factor, leading to a resonance-like te−kt/mt e^{-kt/m} velocity profile before applying the P=F⋅vP = F \cdot v relationship.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMotion in a Straight Line - Class 11 Part 1
ConceptArea Under Acceleration-Time
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree