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Question #42029

Difficulty: 8/10 | 🟢 Free

The Question

Initially at t=0t=0, a system comprising a large parallel-plate capacitor and an uncharged, perfectly conducting solid block placed entirely between its plates is completely field-free. The block contains an internal, empty, eccentric spherical cavity of radius r0r_0. For t>0t > 0, the capacitor is charged such that a uniform displacement current density J⃗d=J0k^\vec{J}_d = J_0 \hat{k} exists in the vacuum region between the plates. An infinitesimal test charge +q0+q_0 is moved from the center of the cavity to its inner surface along a complex path of total length LL at a constant speed vv. What is the magnitude of the total work done by the electromagnetic forces on the test charge during this process?

Options

  • A.

    00

  • B.

    12q0μ0J0vr0L\frac{1}{2} q_0 \mu_0 J_0 v r_0 L

  • C.

    q0J0L22ϵ0v\frac{q_0 J_0 L^2}{2 \epsilon_0 v}

  • D.

    q0μ0J0vL2q_0 \mu_0 J_0 v L^2

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Displacement vs. Total Path Length|Cavity Field Shielding|Equipotential Surface Geometry|Vector Integration

Why This Question Is Tricky

Common Mistakes

This question tests the concept of electromagnetic shielding in perfect conductors, specifically targeting the misconception that external displacement currents or time-varying fields can penetrate an enclosed cavity.

Students often erroneously calculate the induced magnetic field using the Ampere-Maxwell law or the electric field from the displacement current, and then integrate these non-zero forces over the path length LL.

The trap exploits the failure to recognize that a perfect conductor shields not only electrostatic fields (via surface charges) but also time-varying magnetic fields (via induced surface currents), rendering the entire cavity strictly field-free.

Consequently, the Lorentz force is zero everywhere along the path, making the work done identically zero.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMotion in a Straight Line - Class 11 Part 1
ConceptDisplacement vs. Total Path Length
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree