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Question #42027

Difficulty: 8/10 | 🟢 Free

The Question

A solid cylinder of mass mm and radius RR is projected with an initial translational velocity v0v_0 and zero angular velocity on a rough horizontal surface with a coefficient of kinetic friction μk\mu_k. The cylinder experiences slipping before transitioning to pure rolling. Let AvA_v be the area under the velocity-time (v−tv-t) graph and AωA_\omega be the area under the angular velocity-time (ω−t\omega-t) graph from t=0t=0 until the exact moment pure rolling commences. Which of the following expressions correctly represents the total mechanical energy dissipated due to friction during this process?

Options

  • A.

    μkmg(Av−RAω)\mu_k m g (A_v - R A_\omega)

  • B.

    μkmgAv\mu_k m g A_v

  • C.

    μkmg(Av+RAω)\mu_k m g (A_v + R A_\omega)

  • D.

    12μkmg(Av−RAω)\frac{1}{2} \mu_k m g (A_v - R A_\omega)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Velocity-Time Slope-Area Duality|Pure Rolling Condition|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the student's understanding of energy dissipation during the transition from slipping to pure rolling.

A common trap is assuming that the energy dissipated is simply the translational work done by friction (μkmgAv\mu_k m g A_v), ignoring the positive work friction does on the rotational degree of freedom.

By forcing the evaluation of the Work-Energy Theorem through the geometric areas of the v−tv-t and ω−t\omega-t graphs, it exposes the misconception that the 'no-slip' condition (v=ωRv = \omega R) applies during the kinetic phase.

The true dissipation depends strictly on the relative slip distance, represented by the difference between the translational displacement and the rotational arc length.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMotion in a Straight Line - Class 11 Part 1
ConceptVelocity-Time Slope-Area Duality
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree