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Question #42023

Difficulty: 8/10 | 🟢 Free

The Question

A thin converging lens of focal length ff (in air) is placed at the origin x=0x = 0. The region x<0x < 0 is filled with air (refractive index μ=1\mu = 1). The region x>0x > 0 is filled with a transparent medium whose refractive index varies along the x-axis as μ(x)=1+αx\mu(x) = 1 + \alpha x, where α>0\alpha > 0 is a constant. Let F1F_1 be the first focal point (the object position on the principal axis for which the image is formed at infinity) and F2F_2 be the second focal point (the image position for an object at infinity). If a point object is placed at a distance x1x_1 to the left of F1F_1, its image is formed at a distance x2x_2 to the right of F2F_2. Which of the following represents the modified Newton's lens equation for this system?

Options

  • A.

    x1ln⁡(1+αx2e−αf)=αf2x_1 \ln\left(1 + \alpha x_2 e^{-\alpha f}\right) = \alpha f^2

  • B.

    x1x2=f2eαfx_1 x_2 = f^2 e^{\alpha f}

  • C.

    x1ln⁡(1+αx2)=αf2x_1 \ln(1 + \alpha x_2) = \alpha f^2

  • D.

    x1x2=f2αln⁡(1+αf)x_1 x_2 = \frac{f^2}{\alpha} \ln(1 + \alpha f)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

The Directional Sign Convention|Newton’s Form of Lens Equation|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the fundamental origin of Newton's lens equation (x1x2=f2x_1 x_2 = f^2) by placing the system in a medium with a variable refractive index gradient.

Students typically memorize the algebraic Newton's formula and attempt to heuristically modify the focal length (leading to incorrect options like B or D).

However, a continuous refractive index gradient requires integrating the optical path via Snell's law for stratified media.

This integration reveals that the focal length is a local function of the gradient, transforming the standard algebraic relationship into a logarithmic one, while still preserving the core directional sign convention relative to the focal points.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMotion in a Straight Line - Class 11 Part 1
ConceptThe Directional Sign Convention
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree