Start Learning Free

Before You Begin

Question #42017

Difficulty: 8/10 | 🟢 Free

The Question

A Wheatstone bridge consists of four arms forming a quadrilateral ABCDABCD. A battery of EMF V=20 VV = 20\ \text{V} and negligible internal resistance is connected across ACAC, with AA connected to the positive terminal. Arms ABAB, BCBC, and CDCD are made of standard resistors, each of resistance R0=100 ΩR_0 = 100\ \Omega. Arm DADA contains a semiconductor resistor with a temperature-dependent resistance Rs=R0[1−α(T−T0)]R_s = R_0 [1 - \alpha (T - T_0)], where α=1.2×10−4 K−1\alpha = 1.2 \times 10^{-4}\ \text{K}^{-1} and T0T_0 is the ambient temperature.

A galvanometer of resistance Rg=50 ΩR_g = 50\ \Omega is connected across BDBD and reads positive for current flowing from DD to BB. The semiconductor dissipates heat to the surroundings at T0T_0 with a thermal conductance K=10 mW/KK = 10\ \text{mW/K}. Due to a mechanical defect, the galvanometer has a constant zero error IzI_z. In the steady state, the galvanometer reads Iread=550 μAI_{\text{read}} = 550\ \mu\text{A}.

Assuming the change in resistance is small (ΔR≪R0\Delta R \ll R_0) so that first-order perturbation is valid, what is the zero error IzI_z?

Options

  • A.

    150 μA150\ \mu\text{A}

  • B.

    550 μA550\ \mu\text{A}

  • C.

    −250 μA-250\ \mu\text{A}

  • D.

    950 μA950\ \mu\text{A}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Zero Error Correction|Wheatstone Bridge Sensitivity|Drift vs Diffusion Current|Small Angle Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to couple thermal equilibrium with electrical circuit analysis using perturbation methods.

The common trap is assuming the bridge remains balanced or ignoring the dynamic thermal drift of the semiconductor resistor, leading students to incorrectly state Iz=IreadI_z = I_{\text{read}}.

Another trap is incorrectly calculating the power dissipated by using the full voltage VV across the resistor instead of the voltage divider.

The 'Lethal Collision' is realizing that the power dissipation P(R)P(R) has a stationary point at balance (dP/dR=0dP/dR = 0), allowing the use of the unperturbed power V2/4R0V^2/4R_0 to find the exact first-order thermal drift without solving a non-linear feedback equation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterUnits and Measurements - Class 11 Part 1
ConceptZero Error Correction in Instruments
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree