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Question #42012

Difficulty: 8/10 | 🟢 Free

The Question

A semiconductor diode is forward-biased at a constant current. The voltage VV across the diode is given by V(T)=Eg(T)e−βTV(T) = \frac{E_g(T)}{e} - \beta T, where Eg(T)E_g(T) is the temperature-dependent band gap energy, ee is the elementary charge, and β=1.2×10−3 V/K\beta = 1.2 \times 10^{-3} \text{ V/K}. The band gap energy follows the empirical relation Eg(T)=Eg(0)−αT2E_g(T) = E_g(0) - \alpha T^2, where α=1.5×10−6 eV/K2\alpha = 1.5 \times 10^{-6} \text{ eV/K}^2. The diode is used as a temperature sensor by measuring VV with a digital voltmeter having a least count of 4.2 mV4.2 \text{ mV}. What is the minimum temperature change ΔT\Delta T (the 'blind spot') that the voltmeter can resolve at an operating temperature of T=300 KT = 300 \text{ K}?

Options

  • A.

    2.0 K2.0 \text{ K}

  • B.

    3.5 K3.5 \text{ K}

  • C.

    4.7 K4.7 \text{ K}

  • D.

    2.5 K2.5 \text{ K}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Least Count and Resolution Limits|Energy Band Gap Temperature Dependency

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to link the microscopic temperature dependence of a semiconductor's band gap to the macroscopic resolution limits of a measuring instrument.

A common trap is treating the diode's voltage-temperature relationship as purely linear by ignoring the thermal drift of the band gap energy (the αT2\alpha T^2 term), leading to an underestimation of the sensitivity and an incorrect 'blind spot' of 3.5 K3.5 \text{ K}.

Students must correctly differentiate the empirical relation and equate the total derivative ∣dV/dT∣|dV/dT| to the voltmeter's least count to find the true resolution limit.

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Question Information

SubjectPhysics
ChapterUnits and Measurements - Class 11 Part 1
ConceptLeast Count and Resolution Limits
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree