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Question #41935

Difficulty: 8/10 | 🟢 Free

The Question

Let L1L_1 and L2L_2 be two lines in R3\mathbb{R}^3. The direction vector of L1L_1 is given by d1⃗=f1′(1)i^+f2′(1)j^+f3′(1)k^\vec{d_1} = f_1'(1)\hat{i} + f_2'(1)\hat{j} + f_3'(1)\hat{k}, where f1(x)=∫0x3ln⁡∣t−3∣dt,f2(x)=∫0x2ln⁡∣t−5∣dt,f3(x)=∫0x12ln⁡∣t+1∣dtf_1(x) = \int_{0}^{x} 3 \ln|t-3| dt, \quad f_2(x) = \int_{0}^{x} 2 \ln|t-5| dt, \quad f_3(x) = \int_{0}^{x} 12 \ln|t+1| dt The direction vector of L2L_2 is given by d2⃗=g1′(2)i^+g2′(2)j^+g3′(2)k^\vec{d_2} = g_1'(2)\hat{i} + g_2'(2)\hat{j} + g_3'(2)\hat{k}, where g1(x)=∫0x4ln⁡∣t∣dt,g2(x)=∫0x12ln⁡∣t∣dt,g3(x)=∫0x3ln⁡∣t∣dtg_1(x) = \int_{0}^{x} 4 \ln|t| dt, \quad g_2(x) = \int_{0}^{x} 12 \ln|t| dt, \quad g_3(x) = \int_{0}^{x} 3 \ln|t| dt If θ\theta is the acute angle between the lines L1L_1 and L2L_2, then the value of cos⁡θ\cos \theta is:

Options

  • A.

    96169\frac{96}{169}

  • B.

    24169\frac{24}{169}

  • C.

    48169\frac{48}{169}

  • D.

    64169\frac{64}{169}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Angle between two lines|Newton-Leibniz Formula with variable limits|Logarithmic Integration Modulus

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Newton-Leibniz formula combined with the properties of the logarithmic function involving a modulus.

The core trap lies in evaluating the derivative of the integral at a point where the argument of the natural logarithm is negative.

Students often incorrectly assume ln⁡(−x)=−ln⁡x\ln(-x) = -\ln x when trying to resolve a negative argument algebraically, failing to use the proper definition ln⁡∣x∣=ln⁡(−x)\ln|x| = \ln(-x) for x<0x < 0.

This leads to a sign error in the first two components of the direction vector d1⃗\vec{d_1}, changing its proportional direction ratios from (3,4,12)(3, 4, 12) to (−3,−4,12)(-3, -4, 12).

Consequently, the dot product calculation yields an incorrect acute angle of cos⁡−1(24/169)\cos^{-1}(24/169) instead of the correct cos⁡−1(96/169)\cos^{-1}(96/169).

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterThree-Dimensional Geometry - Class 12
ConceptAngle between two lines
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree