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Question #41933

Difficulty: 8/10 | 🟢 Free

The Question

Let L1L_1 and L2L_2 be two lines in 3D space whose direction ratios are respectively given by ⟨a1,b1,c1⟩\langle a_1, b_1, c_1 \rangle and ⟨a2,b2,c2⟩\langle a_2, b_2, c_2 \rangle, where: a1=[3S],b1=[−2S],c1=[4S]a_1 = [ 3 S ], \quad b_1 = [ -2 S ], \quad c_1 = [ 4 S ] a2=[2T],b2=[6T],c2=[3T]a_2 = [ 2 T ], \quad b_2 = [ 6 T ], \quad c_2 = [ 3 T ] Here, [x][x] denotes the greatest integer less than or equal to xx, and the sums SS and TT are defined as: S=∑k=110k(k+1)!S = \sum_{k=1}^{10} \frac{k}{(k+1)!} T=∑k=1241kk+1+(k+1)kT = \sum_{k=1}^{24} \frac{1}{k\sqrt{k+1} + (k+1)\sqrt{k}} Find the angle between the lines L1L_1 and L2L_2.

Options

  • A.

    π2\frac{\pi}{2}

  • B.

    cos⁡−1(3609)\cos^{-1}\left(\frac{3}{\sqrt{609}}\right)

  • C.

    cos⁡−1(6729)\cos^{-1}\left(\frac{6}{7\sqrt{29}}\right)

  • D.

    cos⁡−1(1717)\cos^{-1}\left(\frac{1}{7\sqrt{17}}\right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Angle between two lines|Sum to n terms vs. General Term|Integral Part and Fractional Part

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to handle discrete transformations (Greatest Integer Function) applied to finite series sums.

The primary trap lies in approximating the finite sums SS and TT to their infinite limits (S→1S \to 1, T→1T \to 1).

If a student assumes S=1S = 1, they incorrectly evaluate [3S]=3[3S]=3 instead of 22, and [4S]=4[4S]=4 instead of 33, leading to incorrect direction ratios.

The problem forces exact evaluation of the fractional deficit in the telescoping series before applying the floor function, ultimately revealing orthogonal lines.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterThree-Dimensional Geometry - Class 12
ConceptAngle between two lines
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree