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Question #41921
The Question
Let be a continuous function on such that and for all . Let be the set of all that satisfy the equation . Find the number of elements in .
Options
- A.
0
- B.
1
- C.
2
- D.
3
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Logarithmic Integration Modulus|Mean Value Theorem Applicability|Modulus Sign Dependency
Why This Question Is Tricky
Common Mistakes
This question tests the applicability of the Mean Value Theorem (MVT) in the presence of a modulus-induced cusp, combined with logarithmic integration.
Students often blindly integrate the expression by ignoring the modulus sign dependency, incorrectly finding and subsequently finding 2 false roots for .
Furthermore, even if integrated correctly, students might assume MVT guarantees a solution .
However, because the modulus creates a jump discontinuity in the derivative at , is non-differentiable there, violating MVT's hypothesis.
This creates a 'gap' in the range of the derivative, and the secant slope falls exactly within this gap, resulting in zero solutions.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Differential Equations - Class 12 |
| Concept | Logarithmic Integration Modulus |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |