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Question #41921

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)f(x) be a continuous function on [0,3][0, 3] such that f(0)=0f(0) = 0 and f′(x)=∣x−1∣x−12xx2+1f'(x) = \frac{|x-1|}{x-1} \frac{2x}{x^2+1} for all x∈(0,3)∖{1}x \in (0, 3) \setminus \{1\}. Let SS be the set of all c∈(0,3)c \in (0, 3) that satisfy the equation f′(c)=f(3)−f(0)3f'(c) = \frac{f(3) - f(0)}{3}. Find the number of elements in SS.

Options

  • A.

    0

  • B.

    1

  • C.

    2

  • D.

    3

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Logarithmic Integration Modulus|Mean Value Theorem Applicability|Modulus Sign Dependency

Why This Question Is Tricky

Common Mistakes

This question tests the applicability of the Mean Value Theorem (MVT) in the presence of a modulus-induced cusp, combined with logarithmic integration.

Students often blindly integrate the expression by ignoring the modulus sign dependency, incorrectly finding f(3)=ln⁡10f(3) = \ln 10 and subsequently finding 2 false roots for cc.

Furthermore, even if integrated correctly, students might assume MVT guarantees a solution cc.

However, because the modulus creates a jump discontinuity in the derivative at x=1x=1, f(x)f(x) is non-differentiable there, violating MVT's hypothesis.

This creates a 'gap' in the range of the derivative, and the secant slope falls exactly within this gap, resulting in zero solutions.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDifferential Equations - Class 12
ConceptLogarithmic Integration Modulus
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree