Before You Begin
Question #41837
The Question
For a positive integer , an integer is chosen at random from the set with equal probability. Let be the probability that If satisfies the equation find the sum of all possible valid values of .
Options
- A.
161
- B.
221
- C.
141
- D.
80
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Equiprobable Outcomes|Properties of Binomial Coefficients|Denominator Restriction
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to evaluate probabilities involving binomial sums and their vigilance regarding domain restrictions.
By setting up a probability equation that simplifies to a quadratic, students will find as a root for both the odd and even cases.
The trap is to accept (especially in the even case) without checking the original equation's domain.
Since is in the denominator, makes the probability undefined (division by zero), meaning it must be rejected.
Failing to do so leads to the incorrect sum of 221.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Probability - Class 12 |
| Concept | Equiprobable Outcomes |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |