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Question #41828

Difficulty: 8/10 | 🟢 Free

The Question

Let u⃗=i^+2j^−k^\vec{u} = \hat{i} + 2\hat{j} - \hat{k} and v⃗=2i^−j^+k^\vec{v} = 2\hat{i} - \hat{j} + \hat{k}. A vector w⃗=xi^+yj^+zk^\vec{w} = x\hat{i} + y\hat{j} + z\hat{k} is chosen at random such that x,y,z∈{−1,0,1}x, y, z \in \{-1, 0, 1\}. If PP is the probability that the volume of the parallelepiped formed by u⃗,v⃗\vec{u}, \vec{v}, and w⃗\vec{w} is strictly less than 6, then the value of PP is:

Options

  • A.

    1927\frac{19}{27}

  • B.

    2327\frac{23}{27}

  • C.

    827\frac{8}{27}

  • D.

    2127\frac{21}{27}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Complementary Counting|Scalar Triple Product Volume Logic|Dot Product Projection Sign

Why This Question Is Tricky

Common Mistakes

This question tests the application of complementary counting in 3D geometry while embedding a classic 'Dot Product Projection Sign' trap.

Students often calculate the scalar triple product S=x−3y−5zS = x - 3y - 5z and use complementary counting as 1−P(S≥6)1 - P(S \ge 6).

They forget that geometric volume is the absolute value of the scalar triple product, ∣S∣|S|.

By ignoring the negative projection cases (S≤−6S \le -6), they only subtract half of the unfavorable outcomes, leading directly to the trap answer 23/27.

This penalizes superficial formula application over true spatial reasoning.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterProbability - Class 12
ConceptComplementary Counting
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree