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Question #41783

Difficulty: 8/10 | 🟢 Free

The Question

Let α\alpha and β\beta (α>β\alpha > \beta) be the roots of the quadratic equation x2−3x+1=0x^2 - 3x + 1 = 0. A sequence is defined as Tn=αn−βnT_n = \alpha^n - \beta^n for n∈Nn \in \mathbb{N}. Consider the linear programming problem: Maximize Z=T2x+T1yZ = T_2 x + T_1 y subject to the constraints: 3x+y≤153x + y \le 15 x+2y≤10x + 2y \le 10 x≥0,y≥0x \ge 0, y \ge 0 If SS is the set of all points (x,y)(x,y) in the feasible region at which ZZ attains its maximum value, find the value of ∫S(x+y) ds\int_S (x+y) \, ds, where dsds is the arc length element along SS.

Options

  • A.

    6106\sqrt{10}

  • B.

    5105\sqrt{10}

  • C.

    15515\sqrt{5}

  • D.

    3103\sqrt{10}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Corner Point Method Precision|Multiple Optimal Solutions|Quadratic Roots in Sequences

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of sequence evaluation involving irrational roots and the Corner Point Method in Linear Programming.

The primary trap lies in the non-integer coefficients of the objective function (353\sqrt{5} and 5\sqrt{5}), which often causes students to doubt their calculations or fail to recognize that the slope of the objective function exactly matches the active constraint 3x+y≤153x+y \le 15.

Consequently, they might only identify a single optimal point instead of the entire line segment (Multiple Optimal Solutions).

The final integration step over the solution set SS rigorously verifies if the student has correctly identified SS as a continuous segment rather than discrete points, punishing those who merely find the maximum value of ZZ.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLinear Programming - Class 12
ConceptCorner Point Method Precision
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree