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Question #41771
The Question
Let . Find the maximum value of the function on the set .
Options
- A.
- B.
12
- C.
6
- D.
\text{Does not exist}
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Objective Function Gradient|Tangent/Normal Slope Interplay|Closed vs Open Intervals
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to optimize a linear objective function over a region with non-linear constraints while navigating the topological trap of open boundaries.
Students typically use parametric coordinates or Lagrange multipliers to find the critical point where the gradient of the objective function aligns with the normal of the ellipse.
The trap lies in the Weierstrass Extreme Value Theorem: because the constraint is a strict inequality, the domain is not compact.
The unique global maximum of the objective function on the closed ellipse lies exactly on this excluded boundary.
Consequently, the function approaches a supremum but never actually attains it within the set , meaning the maximum does not exist.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Linear Programming - Class 12 |
| Concept | Objective Function Gradient |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |