Start Learning Free

Before You Begin

Question #41770

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the set of all points (x,y)(x,y) in the Cartesian plane that maximize the objective function Z=2x+2yZ = 2x + 2y subject to the condition that the function f(x,y)=sin⁡−1(x−y)+sec⁡−1(4x+y)f(x,y) = \sqrt{\sin^{-1}(x-y)} + \sec^{-1}\left(\frac{4}{x+y}\right) is real-valued. Find the length of the line segment SS.

Options

  • A.

    12\frac{1}{\sqrt{2}}

  • B.

    2\sqrt{2}

  • C.

    0

  • D.

    222\sqrt{2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Unbounded Region Trap|Multiple Optimal Solutions|Domain Constraint Intersections

Why This Question Is Tricky

Common Mistakes

This question tests the 'Multiple Optimal Solutions' concept in Linear Programming, masked by 'Domain Constraint Intersections' of inverse trigonometric functions.

Students often mistakenly assume sec⁡−1(u)\sec^{-1}(u) implies ∣u∣≤1|u| \le 1, leading to an unbounded region ∣x+y∣≥4|x+y| \ge 4 (Unbounded Region Trap).

Furthermore, the square root over sin⁡−1(x−y)\sin^{-1}(x-y) restricts its argument to [0,1][0, 1] rather than [−1,1][-1, 1].

Missing this yields a false segment length of 2\sqrt{2}.

Finally, because the objective function is parallel to the boundary x+y=4x+y=4, the maximum is attained along a segment rather than a single vertex, punishing students who only check corner points and assume a unique solution (length 0).

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLinear Programming - Class 12
ConceptUnbounded Region Trap
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree