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Question #41749
The Question
Let such that the system of linear equations has a non-trivial solution. Let be a line with direction ratios . If the orthogonal projection of the line onto a plane is a single point, and passes through the point , then the square of the perpendicular distance from the point to the plane is:
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Orthogonal projection of a line|Collinearity vs Coplanarity|Skew-Symmetric Determinant|Factor Theorem in Determinants
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of algebraic determinant properties and geometric degeneracy.
Students often try to brute-force expand the determinant, leading to a messy cubic equation prone to algebraic errors.
The trap relies on recognizing the matrix as a perturbed skew-symmetric matrix .
By applying the Factor Theorem, students can immediately deduce that is a factor because setting leaves a purely skew-symmetric matrix of odd order, whose determinant is identically zero.
Furthermore, the geometric condition that the 'orthogonal projection of a line onto a plane is a point' is a conceptual trap; it simply means the line is perpendicular to the plane (degenerate projection), meaning the line's direction ratios become the plane's normal vector.
Failing to decode this geometric degeneracy prevents the formulation of the plane's equation.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Three-Dimensional Geometry - Class 12 |
| Concept | Orthogonal projection of a line |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |