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Question #41736

Difficulty: 8/10 | 🟢 Free

The Question

Let A=(1−1221−14−13)A = \begin{pmatrix} 1 & -1 & 2 \\ 2 & 1 & -1 \\ 4 & -1 & 3 \end{pmatrix} and B=(121012101)B = \begin{pmatrix} 1 & 2 & 1 \\ 0 & 1 & 2 \\ 1 & 0 & 1 \end{pmatrix}. Let Π\Pi be the plane consisting of all points (x,y,z)(x, y, z) such that the matrix equation BA(uvw)=(xyz)BA \begin{pmatrix} u \\ v \\ w \end{pmatrix} = \begin{pmatrix} x \\ y \\ z \end{pmatrix} has at least one solution for (u,v,w)∈R3(u, v, w) \in \mathbb{R}^3. If dd is the perpendicular distance from the point P(1,−1,1)P(1, -1, 1) to the plane Π\Pi, then the value of dd is:

Options

  • A.

    705\frac{\sqrt{70}}{5}

  • B.

    0

  • C.

    27035\frac{2\sqrt{70}}{35}

  • D.

    707\frac{\sqrt{70}}{7}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Distance from point to plane|Singular vs Non-Singular Matrices|Matrix Multiplication Non-Commutativity

Why This Question Is Tricky

Common Mistakes

This question tests the understanding of column spaces and matrix transformations, specifically targeting the non-commutativity of matrix multiplication (C(BA)≠C(AB)C(BA) \neq C(AB)).

Students often mistakenly assume that since BB is invertible, the column space of BABA is identical to the column space of AA (which is only true for ABAB).

If a student falls for this trap and uses the column space of AA (or ABAB), they will derive the incorrect plane equation 2x+y−z=02x + y - z = 0.

The point P(1,−1,1)P(1, -1, 1) is intentionally chosen to lie exactly on this incorrect plane, yielding a distance of 00 (Option B), heavily punishing the commutativity assumption.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterThree-Dimensional Geometry - Class 12
ConceptDistance from point to plane
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree