Start Learning Free

Before You Begin

Question #41727

Difficulty: 8/10 | 🟢 Free

The Question

Let XX be a random variable representing the number of successes in n=280n = 280 independent Bernoulli trials. The probability of success in a single trial is given by pp, where p=∫0π/22sin⁡280x+sin⁡(2x)2(sin⁡280x+cos⁡280x+sin⁡(2x)) dxp = \int_0^{\pi/2} \frac{2\sin^{280} x + \sin(2x)}{2(\sin^{280} x + \cos^{280} x + \sin(2x))} \, dx Find the value of 16π2E[X2−X]\frac{16}{\pi^2} E[X^2 - X].

Options

  • A.

    78120

  • B.

    78400

  • C.

    39060

  • D.

    19530

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Random Variable Expectation|Bernoulli Trials Logic|Definite Integral Properties (King's Property)

Why This Question Is Tricky

Common Mistakes

This question tests the application of King's Property in definite integrals to find a transcendental probability parameter pp, followed by the computation of the second factorial moment of a Binomial distribution.

The primary trap lies in the algebraic fatigue and potential for error if students attempt to calculate E[X2]E[X^2] and E[X]E[X] separately, as the transcendental nature of p=π/4p = \pi/4 creates messy intermediate terms (like 70π70\pi) that must perfectly cancel.

Furthermore, the distracting constant '280' in the integral's exponents is designed to break perceived symmetry and intimidate, while option B (7840078400) traps students who incorrectly approximate E[X2−X]E[X^2 - X] as n2p2n^2p^2.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterProbability - Class 12
ConceptRandom Variable Expectation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree