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Question #41725

Difficulty: 8/10 | 🟢 Free

The Question

Let A=(3p−2tan⁡θ−cot⁡θq)A = \begin{pmatrix} 3p - 2 & \tan \theta \\ -\cot \theta & q \end{pmatrix}, where p∈(0,1)p \in (0, 1), q∈Rq \in \mathbb{R}, and θ∈(0,π2)\theta \in \left(0, \frac{\pi}{2}\right). It is given that AA is a nilpotent matrix of index 2. If pp represents the probability of success in a single trial of a binomial experiment, find the probability of at least 4 successes in 6 independent trials.

Options

  • A.

    73729\frac{73}{729}

  • B.

    64729\frac{64}{729}

  • C.

    31243\frac{31}{243}

  • D.

    20243\frac{20}{243}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Binomial Distribution Tail-Ends|Nilpotent Matrix Logic|Matrix Equality|Implicit to Explicit Conversion

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of linear algebra and probability.

The primary trap lies in the implicit-to-explicit conversion of the matrix parameters.

Students often attempt to manually compute A2=OA^2 = O and solve the resulting system of non-linear equations, which is algebraically heavy and prone to error.

The elegant approach requires recognizing that for any 2×22 \times 2 nilpotent matrix of index 2, both the trace and determinant must strictly be zero.

A secondary trap is the boundary condition of probability: solving the determinant equation yields two roots (p=1p=1 and p=1/3p=1/3), and failing to reject p=1p=1 (since p∈(0,1)p \in (0,1) is given) leads to a degenerate binomial distribution and an incorrect tail-end probability.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterProbability - Class 12
ConceptBinomial Distribution Tail-Ends
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree