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Question #41708

Difficulty: 8/10 | 🟢 Free

The Question

Let S={−2,−1,0,1,2}S = \{-2, -1, 0, 1, 2\}. A point Q(a,b,c)Q(a, b, c) is chosen uniformly at random such that a,b,c∈Sa, b, c \in S. Let PP be the point (1,1,1)(1, 1, 1) and Π\Pi be the plane x+y+z=0x + y + z = 0. What is the probability that the line segment PQPQ intersects the plane Π\Pi?

Options

  • A.

    72125\frac{72}{125}

  • B.

    2125\frac{21}{25}

  • C.

    2325\frac{23}{25}

  • D.

    53125\frac{53}{125}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Sample Space Partitioning|Line-Plane intersection logic|Parametric form pitfalls

Why This Question Is Tricky

Common Mistakes

This question tests the boundary conditions of parametric line equations in 3D geometry, a common pitfall in sample space partitioning.

Students frequently find the intersection of the line with the plane (t∈Rt \in \mathbb{R}) or the ray (t≥0t \ge 0), forgetting that for a line segment PQPQ, the parameter tt must strictly satisfy t∈[0,1]t \in [0, 1].

Ignoring this upper bound leads to the trap answers 23/25 or 21/25, incorrectly expanding the favorable sample space by including intersections that occur outside the segment.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterProbability - Class 12
ConceptSample Space Partitioning
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree