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Question #41663

Difficulty: 8/10 | 🟢 Free

The Question

For each integer n≥1n \ge 1, let EnE_n be a plane whose intercepts An,Bn,CnA_n, B_n, C_n on the x,y,zx, y, z axes respectively satisfy: 1An=∑r=0n(nr)2,1Bn=∑r=0nr(nr)2,1Cn=∑r=0nr2(nr)2\frac{1}{A_n} = \sum_{r=0}^n \binom{n}{r}^2, \quad \frac{1}{B_n} = \sum_{r=0}^n r \binom{n}{r}^2, \quad \frac{1}{C_n} = \sum_{r=0}^n r^2 \binom{n}{r}^2 Evaluate the sum: ∑n=120(1−AnCnBn2)−1\sum_{n=1}^{20} \left( 1 - \frac{A_n C_n}{B_n^2} \right)^{-1}

Options

  • A.

    420

  • B.

    210

  • C.

    840

  • D.

    400

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Variable plane intercepts|Vandermonde's Identity|Coefficient of x^r in Expansion|Parametric form pitfalls

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to algebraically manipulate binomial sums using Vandermonde's Identity and its derivatives, framed within 3D geometry.

The primary trap lies in the non-linear dependency of the plane's intercepts.

Students often attempt to calculate the first few terms manually to guess a pattern, but calculation errors in S2S_2 (due to the r2r^2 term) are extremely common.

The rigorous path requires recognizing that rr and r2r^2 can be absorbed into the binomial coefficients via r(nr)=n(n−1r−1)r\binom{n}{r} = n\binom{n-1}{r-1}, transforming the complex sums into standard Vandermonde convolutions.

Failing to express all sums as scalar multiples of (2nn)\binom{2n}{n} leads to an algebraic dead end.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterThree-Dimensional Geometry - Class 12
ConceptVariable plane intercepts
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree