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Question #41636
The Question
A line passes through the origin and has direction ratios . A point lies on the line at a distance () from . The point satisfies the condition and its distance satisfies . Find the sum of all possible integral values of .
Options
- A.
14
- B.
3
- C.
25
- D.
11
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Parametric form pitfalls|Direction Cosines constraint|Wavy Curve (Method of Intervals)|General Solution Principal Values
Why This Question Is Tricky
Common Mistakes
The student uses the parametric form of a line to express coordinates in terms of the distance parameter .
The primary pitfall arises when solving the resulting trigonometric inequality: students often restrict themselves to the principal values (e.g., ), ignoring the general solution and the periodic nature of the constraint.
Furthermore, combining this with the Wavy Curve method requires careful intersection of discrete valid integers from disjoint intervals.
Failing to account for the periodicity leads to missing valid segments of the line (such as ), resulting in an incomplete set of points and an incorrect sum.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Three-Dimensional Geometry - Class 12 |
| Concept | Parametric form pitfalls |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |