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Question #41630
The Question
Let and be two planes. Let be a plane passing through the line of intersection of and , and bisecting one of the angles between them. The normal vector to the plane is chosen such that are coprime integers with . It is given that the projection of onto the -plane is a vector whose tip lies on the director circle of the ellipse (assuming its tail is at the origin). If intersects the coordinate axes at points and , then the area of is:
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Equation of plane through intersection|Angle Bisector Direction|Director Circle Locus|Angle Bisector Logic
Why This Question Is Tricky
Common Mistakes
The question tests the student's ability to synthesize 3D geometry (angle bisectors of planes) with 2D coordinate geometry (director circle of an ellipse).
The primary trap lies in the selection of the correct bisector.
Students often memorize the acute/obtuse angle bisector conditions () and might blindly apply them, assuming the question implies one of these standard geometric properties.
By introducing the director circle locus as a projection constraint on the normal vector, the problem forces an analytical verification.
Furthermore, confusing the director circle () with the auxiliary circle () will lead to a dead end, acting as a secondary conceptual trap.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Three-Dimensional Geometry - Class 12 |
| Concept | Equation of plane through intersection |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |