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Question #41624

Difficulty: 8/10 | 🟢 Free

The Question

Let PP be the point that divides the line segment joining the points A(1,−2,3)A(1, -2, 3) and B(4,7,−6)B(4, 7, -6) internally in the ratio 1:21:2. Let cc be the perpendicular distance of point PP from the yzyz-plane. Consider the function f(x)=x2−5x−3∣x−c∣f(x) = x^2 - 5x - 3|x - c| defined on the interval [1,5][1, 5]. If MM and mm are the absolute maximum and absolute minimum values of f(x)f(x) on the given interval respectively, then the value of M+mM + m is:

Options

  • A.

    −16-16

  • B.

    −17-17

  • C.

    −14-14

  • D.

    −19-19

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Section Formula Internals|Global Extrema on Intervals|Modulus Sign Dependency

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of 3D coordinate geometry and calculus.

The section formula determines a geometric parameter cc that acts as the critical boundary for a modulus function.

The primary trap lies in the non-differentiability of the modulus at x=2x=2.

Students who rely solely on setting the derivative to zero will find critical points at x=1x=1 and x=4x=4, completely missing the local maximum at the non-differentiable point x=2x=2.

Since f(2)=−6f(2) = -6 is strictly greater than the boundary values f(1)=−7f(1) = -7 and f(5)=−9f(5) = -9, ignoring the modulus boundary leads to an incorrect absolute maximum and a wrong final sum.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterVector Algebra - Class 12
ConceptSection Formula Internals
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree