Before You Begin
Question #41624
The Question
Let be the point that divides the line segment joining the points and internally in the ratio . Let be the perpendicular distance of point from the -plane. Consider the function defined on the interval . If and are the absolute maximum and absolute minimum values of on the given interval respectively, then the value of is:
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Section Formula Internals|Global Extrema on Intervals|Modulus Sign Dependency
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of 3D coordinate geometry and calculus.
The section formula determines a geometric parameter that acts as the critical boundary for a modulus function.
The primary trap lies in the non-differentiability of the modulus at .
Students who rely solely on setting the derivative to zero will find critical points at and , completely missing the local maximum at the non-differentiable point .
Since is strictly greater than the boundary values and , ignoring the modulus boundary leads to an incorrect absolute maximum and a wrong final sum.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Vector Algebra - Class 12 |
| Concept | Section Formula Internals |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |