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Question #41607

Difficulty: 8/10 | 🟢 Free

The Question

Let y=y(x)y = y(x) be the solution to the differential equation xdydx+(1−2x∣x−1∣)y=x2(1−x)y2x \frac{dy}{dx} + (1 - 2x|x-1|) y = x^2(1-x) y^2 for x>0x > 0, satisfying the condition lim⁡x→0xy(x)=22e−1\lim_{x \to 0} x y(x) = \frac{2}{2e - 1}. Find the value of y(2)y(2).

Options

  • A.

    11

  • B.

    12e−1\frac{1}{2e - 1}

  • C.

    22e−1\frac{2}{2e - 1}

  • D.

    e−12e - \frac{1}{2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Bernoulli Equation Transformation|Integrating f(x) + xf'(x) forms|The Modulus Trap

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to recognize the d(xy)d(xy) exact differential form hidden within a Bernoulli equation, followed by a critical modulus trap in the resulting linear differential equation.

The integrating factor depends on ∣x−1∣|x-1|, forcing a domain bifurcation at x=1x=1.

Students who blindly integrate without splitting the domain will incorrectly assume a single constant of integration, leading to the trap answer 1/(2e−1)1/(2e-1).

The problem rigorously evaluates piecewise continuity of the transformed variable u(x)u(x) to find the correct global solution.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDifferential Equations - Class 12
ConceptBernoulli Equation Transformation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree