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Question #41606
The Question
Let be the solution to the initial value problem with , defined on its maximal interval of existence. Let be the set of all possible values of . Find .
Options
- A.
{ e - 1 }
- B.
{ 1 - e }
- C.
{ 0 }
- D.
\emptyset
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Integrating Factor (IF) Sign Sensitivity|Variable Separable Constraints|Extraneous Solution Rejection
Why This Question Is Tricky
Common Mistakes
This question tests Integrating Factor (IF) sign sensitivity and Extraneous Solution Rejection.
By forcing a variable separable transformation via the IF method, the DE reveals a singularity at x=1.
This jump discontinuity means the initial value problem cannot be extended across x=1.
Students who ignore the IF sign will incorrectly match the branches and obtain an extraneous value for f(1/e).
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Differential Equations - Class 12 |
| Concept | Integrating Factor (IF) Sign Sensitivity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |