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Question #41595
The Question
Let be the solution to the differential equation for , satisfying the initial condition . Find the value of .
Options
- A.
- B.
- C.
- D.
3
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Homogeneous Function Homogeneity|Parametric Form Manipulation|Modulus Inequality Logic
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to rigorously handle domain restrictions imposed by modulus functions within homogeneous differential equations.
The trap lies in the absolute value , which translates to in the parametric form.
Students commonly drop the modulus or assume the initial branch holds globally, leading to the extraneous solution for all .
By evaluating at , which lies beyond the critical transition point , the problem forces the student to recognize that exceeds , requiring a piecewise integration and recalculation of the integration constant to maintain continuity of the solution curve.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Differential Equations - Class 12 |
| Concept | Homogeneous Function Homogeneity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |