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Question #41594

Difficulty: 8/10 | 🟢 Free

The Question

Let f:R→(0,∞)f: \mathbb{R} \to (0, \infty) be a differentiable function satisfying f(0)=1f(0) = 1 and f′(x)=f(x)(1+2xx2+1)+(x2+1)2f(x)−2(x2+1)f'(x) = f(x) \left( 1 + \frac{2x}{x^2+1} \right) + \frac{(x^2+1)^2}{f(x)} - 2(x^2+1) for all x∈Rx \in \mathbb{R}. Find the value of f(3)f(3).

Options

  • A.

    8

  • B.

    9

  • C.

    10

  • D.

    12

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Variable Separable Constraints|Arithmetic Mean Inequality|Constant Function Logic|Identity Function Behavior

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to identify singular solutions in non-linear differential equations.

The standard algorithmic approach of separating variables requires dividing by (y−1)2(y-1)^2, which implicitly assumes y≠1y \neq 1.

Students who blindly integrate will obtain ln⁡∣y−1∣−1y−1=x+C\ln|y-1| - \frac{1}{y-1} = x + C.

Applying the initial condition y(0)=1y(0)=1 yields an undefined LHS, leading many to incorrectly conclude that no solution exists or to make algebraic errors forcing a fit.

The trap is failing to recognize that the constant function y=1y=1 (derived via the AM-GM inequality structure y+1/y≥2y + 1/y \ge 2) is a valid singular solution that perfectly satisfies both the ODE and the boundary condition, yielding f(x)=x2+1f(x) = x^2+1.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDifferential Equations - Class 12
ConceptVariable Separable Constraints
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree