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Question #41585

Difficulty: 8/10 | 🟢 Free

The Question

Let y=y(x)y = y(x) be a function satisfying the differential equation: (d2ydx2)2−(dydx)2d2ydx2−dydx=d2ydx2+dydx+(dydx)3−x\frac{ \left( \frac{d^2y}{dx^2} \right)^2 - \left( \frac{dy}{dx} \right)^2 }{ \frac{d^2y}{dx^2} - \frac{dy}{dx} } = \frac{d^2y}{dx^2} + \frac{dy}{dx} + \left( \frac{dy}{dx} \right)^3 - x If OO and DD represent the order and degree of this differential equation respectively, then the ordered pair (O,D)(O, D) is:

Options

  • A.

    (2,1)(2, 1)

  • B.

    (2,2)(2, 2)

  • C.

    (1,3)(1, 3)

  • D.

    (1,1)(1, 1)

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Order and Degree Definition|Implicit Differentiation Implicit Domain|Cross Multiplication Trap

Why This Question Is Tricky

Common Mistakes

This question tests the 'Implicit Domain' and 'Cross Multiplication Trap' in finding the order and degree of a differential equation.

Students often cross-multiply to clear denominators and form a polynomial in derivatives, arriving at 0=(y′′−y′)((y′)3−x)0 = (y'' - y')((y')^3 - x).

A common mistake is to stop here and identify the highest derivative as y′′y'' with a power of 1, incorrectly concluding the order is 2 and degree is 1.

However, the original equation's denominator dictates the implicit domain constraint y′′−y′≠0y'' - y' \neq 0.

Recognizing this forces the student to divide out the extraneous factor, dropping the order to 1 and revealing the true degree of 3.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDifferential Equations - Class 12
ConceptOrder and Degree Definition
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree