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Question #41561

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=∣x∣f(x) = |x| and g(x)=x∣x−2∣−1g(x) = x|x-2| - 1. Evaluate the integral ∫03f(g(x)) dx\int_{0}^{3} f(g(x)) \, dx

Options

  • A.

    82−73\frac{8\sqrt{2} - 7}{3}

  • B.

    1

  • C.

    82+13\frac{8\sqrt{2} + 1}{3}

  • D.

    42−13\frac{4\sqrt{2} - 1}{3}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

The Modulus Trap|Composition Continuity|Wavy Curve (Method of Intervals)

Why This Question Is Tricky

Common Mistakes

This question tests the 'Modulus Trap' within composite functions.

Students often correctly identify the critical point of the inner modulus (x=2x=2) but fail to apply the Method of Intervals to the resulting piecewise quadratic x2−2x−1x^2-2x-1 on [2,3][2, 3].

By neglecting the new root x=1+2x=1+\sqrt{2} introduced by the composition f(g(x))f(g(x)), they integrate across a sign change, leading to the incorrect answer of 1.

It enforces rigorous case-based decomposition.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Integrals - Class 12
ConceptThe Modulus Trap
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree