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Question #41550

Difficulty: 8/10 | 🟢 Free

The Question

A curve C1C_1 passing through the origin has the property that any ray of light moving parallel to the xx-axis reflects off C1C_1 and passes through the point S(1,0)S(1,0). Let C2C_2 be an ellipse whose foci are the origin and SS, and whose major axis has length 22. If AA is the area of the region bounded by C1C_1 and C2C_2 containing the point (12,0)\left(\frac{1}{2}, 0\right), then AA equals:

Options

  • A.

    5627+π34+32sin⁡−1(13)\frac{5\sqrt{6}}{27} + \frac{\pi\sqrt{3}}{4} + \frac{\sqrt{3}}{2}\sin^{-1}\left(\frac{1}{3}\right)

  • B.

    5654+π38+34sin⁡−1(13)\frac{5\sqrt{6}}{54} + \frac{\pi\sqrt{3}}{8} + \frac{\sqrt{3}}{4}\sin^{-1}\left(\frac{1}{3}\right)

  • C.

    −627+π34−32sin⁡−1(13)-\frac{\sqrt{6}}{27} + \frac{\pi\sqrt{3}}{4} - \frac{\sqrt{3}}{2}\sin^{-1}\left(\frac{1}{3}\right)

  • D.

    5627+π34−32sin⁡−1(13)\frac{5\sqrt{6}}{27} + \frac{\pi\sqrt{3}}{4} - \frac{\sqrt{3}}{2}\sin^{-1}\left(\frac{1}{3}\right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Symmetry Utilization|Reflective Property|Intersection of Conics

Why This Question Is Tricky

Common Mistakes

This problem tests the translation of physical reflective properties into geometric loci to identify the parabola.

The primary trap lies in the intersection of the two conics, which yields a quadratic in xx with an extraneous negative root x=−9/2x = -9/2.

Students often fail to discard this root, leading to incorrect integration limits.

Furthermore, the integration requires splitting the domain at the correct intersection point x=1/6x = 1/6 and carefully managing the sign of the lower limit in the trigonometric substitution.

Forgetting the symmetry multiplier of 2 is another classic pitfall designed to catch rushed calculations.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Integrals - Class 12
ConceptSymmetry Utilization
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree