Before You Begin
Question #41544
The Question
Let be the set of all points in the Cartesian plane that satisfy the system of equations: Find the number of integer values of such that the inequality holds true for all points .
Options
- A.
4
- B.
5
- C.
6
- D.
7
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Intersection Point Accuracy|Intersection of Conics|Modulus Inequality Logic|Cross Multiplication Trap
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to accurately find the intersection of two conics and correctly apply modulus inequalities.
The primary trap lies in the cross-multiplication of the rational inequality.
Students often blindly cross-multiply the term to the right side without evaluating its sign.
Since for all intersection points, , which is negative.
Cross-multiplying without flipping the inequality sign leads to the erroneous condition , yielding 4 integer values instead of the correct 6.
This perfectly discriminates students who rely on rote algebraic manipulation from those who maintain rigorous logical checks on domain and signs.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Application of Integrals - Class 12 |
| Concept | Intersection Point Accuracy |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |