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Question #41533

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the region in the xyxy-plane defined by S={(x,y):x2+y2≤4 and (y−[x])(x3−x2−x+1)≤0}S = \left\{ (x,y) : x^2 + y^2 \le 4 \text{ and } (y - [x])(x^3 - x^2 - x + 1) \le 0 \right\} where [x][x] denotes the greatest integer less than or equal to xx. The area of the region SS is:

Options

  • A.

    3π−23\pi - 2

  • B.

    7π3−23\frac{7\pi}{3} - 2\sqrt{3}

  • C.

    5π3+3−2\frac{5\pi}{3} + \sqrt{3} - 2

  • D.

    3π−33\pi - \sqrt{3}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

The Sign-Consistency Principle|Standard Ellipse/Circle Area|Even Multiplicity Roots|Greatest Integer Function Traps

Why This Question Is Tricky

Common Mistakes

This question tests the Sign-Consistency Principle and integration over piecewise domains defined by the Greatest Integer Function (GIF).

The primary trap lies in the polynomial (x3−x2−x+1)(x^3 - x^2 - x + 1), which factors into (x+1)(x−1)2(x+1)(x-1)^2.

Students relying on rote 'plus-minus-plus' sign alternation will incorrectly assume a sign change at the even multiplicity root x=1x=1.

This leads them to evaluate the interval [1,2)[1, 2) under the wrong condition y≥1y \ge 1 instead of y≤1y \le 1, yielding the trap answer 7π3−23\frac{7\pi}{3} - 2\sqrt{3}.

Furthermore, the GIF forces candidates to carefully partition the circular domain and compute non-trivial geometric sub-regions, filtering out those who cannot integrate circular segments bounded by off-center horizontal lines.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterApplication of Integrals - Class 12
ConceptThe Sign-Consistency Principle
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree