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Question #41528

Difficulty: 8/10 | 🟢 Free

The Question

Let M(x)M(x) be a 7×77 \times 7 matrix whose elements are given by mi,j=(−1)kx6−km_{i,j} = (-1)^k x^{6-k}, where k∈{0,1,…,6}k \in \{0, 1, \dots, 6\} such that k≡(j−i)(mod7)k \equiv (j-i) \pmod 7 for 1≤i,j≤71 \le i, j \le 7. If f(x)=det⁡(M(x))f(x) = \det(M(x)), then the value of ∫01(f(x)+xf′(x)) dx\int_0^1 (f(x) + x f'(x)) \, dx is

Options

  • A.

    0

  • B.

    64

  • C.

    128

  • D.

    256

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Integrating f(x) + xf'(x) forms|Roots of Unity Properties|Determinant Product Rule

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of integration by parts (reverse product rule) and the spectral properties of circulant matrices.

A common trap is attempting to expand the 7×77 \times 7 determinant algebraically or numerically, which is extremely time-consuming and prone to error.

Another trap lies in evaluating the product of the roots of unity ∏(1+ωr)\prod (1+\omega^r); students often incorrectly assume it equals 1 or 0 due to cyclic symmetry, leading to answers like 128 or 0.

Recognizing the circulant eigenvalue formula λr=∑ckωrk\lambda_r = \sum c_k \omega^{rk} and leveraging the polynomial roots of zn−1z^n-1 is the intended high-level heuristic.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntegrals - Class 12
ConceptIntegrating f(x) + xf'(x) forms
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree