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Question #41518

Difficulty: 8/10 | 🟢 Free

The Question

Let PP and QQ be 2×22 \times 2 real matrices such that P2=Q2=IP^2 = Q^2 = I and PQ+QP=0PQ + QP = \mathbf{0}, where II is the identity matrix and 0\mathbf{0} is the zero matrix. Let A(x)=Psin⁡2x+Qcos⁡2xA(x) = P \sin^2 x + Q \cos^2 x and B(x)=Pcos⁡2x+Qsin⁡2xB(x) = P \cos^2 x + Q \sin^2 x. Define the function f(x)=det⁡(ddx(A(x)B(x)))f(x) = \det \left( \frac{d}{dx} (A(x) B(x)) \right). Find the value of 4π∫0π/2f(x) dx\frac{4}{\pi} \int_0^{\pi/2} f(x) \, dx.

Options

  • A.

    1

  • B.

    3

  • C.

    5

  • D.

    8

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Wallis' Formula|Differentiation of Determinants|Matrix Multiplication Non-Commutativity

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to handle the differentiation of matrix products and determinants involving non-commutative matrices.

The primary trap lies in the product rule for matrices: students often incorrectly assume commutativity and write ddx(AB)=A′B+B′A\frac{d}{dx}(AB) = A'B + B'A instead of A′B+AB′A'B + AB'.

If they make this error, the PQPQ terms cancel out, leading to an incorrect determinant of sin⁡24x\sin^2 4x and a final answer of 1.

Furthermore, it elegantly bridges abstract linear algebra (anti-commuting involutory matrices) with calculus (Wallis' integral properties), a hallmark of high-tier JEE Advanced problems.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntegrals - Class 12
ConceptWallis' Formula
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree