Before You Begin
Question #41516
The Question
Let be the set of all integers satisfying the equation Find the sum of all elements in .
Options
- A.
930
- B.
1830
- C.
900
- D.
1860
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Bridge
Practice problems that bridge the gap between foundational theory and advanced practical application.
Concepts Behind This Question
Reduction Formulae|Vandermonde's Identity|Greatest Binomial Coefficient
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of Wallis' reduction formula and Vandermonde's identity, while setting a parity trap.
The core trap exploits the common student oversight of ignoring the domain constraints of Wallis' formula, where the presence of strictly depends on the parity of the exponent.
Students who blindly equate the integral's coefficient to the binomial sum without checking for odd/even cases will incorrectly assume the identity holds for all integers, leading them to sum all numbers in the interval (yielding the distractor 1830).
By forcing the evaluation of an integral that must match an integer binomial coefficient, the problem demands the recognition that the irrationality of the odd case acts as a strict boundary constraint, restricting valid solutions exclusively to even integers.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Integrals - Class 12 |
| Concept | Reduction Formulae |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |