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Question #41515

Difficulty: 8/10 | 🟢 Free

The Question

Let In=∫01xn1+x2 dxI_n = \int_0^1 \frac{x^n}{1+x^2} \, dx for n≥1n \ge 1. A family of curves is given by the equation y2=2kx+cx2y^2 = 2kx + cx^2, where cc is an arbitrary constant and k=4(I5+I3)k = 4(I_5 + I_3). Which of the following represents the orthogonal trajectories of this family of curves? (Here CC is an arbitrary constant of integration)

Options

  • A.

    x2+2y2ln⁡∣y∣=Cy2x^2 + 2y^2 \ln|y| = C y^2

  • B.

    x2−2y2ln⁡∣y∣=Cy2x^2 - 2y^2 \ln|y| = C y^2

  • C.

    y2+2x2ln⁡∣x∣=Cx2y^2 + 2x^2 \ln|x| = C x^2

  • D.

    y2−2x2ln⁡∣x∣=Cx2y^2 - 2x^2 \ln|x| = C x^2

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Reduction Formulae|Arbitrary Constants vs Parameters|Orthogonal Trajectories

Why This Question Is Tricky

Common Mistakes

This question tests the conceptual distinction between an arbitrary constant of a family of curves and a fixed parameter defined by a reduction formula.

The trap lies in the elimination step: students often reflexively differentiate to eliminate all constants.

If the reduction constant kk is mistakenly treated as the arbitrary constant to be eliminated (instead of cc), it leads to an entirely incorrect differential equation (2xyy′−y2−cx2=02xyy' - y^2 - cx^2 = 0).

By forcing the evaluation of kk via a reduction formula first, the problem ensures kk is recognized as a fixed numerical parameter (k=1k=1) that must remain in the differential equation, while cc is eliminated to find the correct orthogonal trajectory.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterIntegrals - Class 12
ConceptReduction Formulae
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree