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Question #41511
The Question
Let denote the indicator function of the set , which equals if and otherwise. For , define the function: Evaluate the limit:
Options
- A.
- B.
- C.
1
- D.
2
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Monster
Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.
Concepts Behind This Question
Definite Integral Properties (King's Property)|Indicator Function Logic|Equiprobability Fallacy|Indeterminate Forms
Why This Question Is Tricky
Common Mistakes
This question tests the application of King's Property disguised by an indicator function, followed by resolving an indeterminate form using the Leibniz rule.
The primary trap is the 'Equiprobability Fallacy', where students misinterpret the indicator function as implying a uniform density or fail to divide by 2 after applying King's Property, leading to incorrect limits like or .
Furthermore, careless application of L'Hôpital's rule on the composite trigonometric denominator often results in missing the factor of 2 from the chain rule, trapping students into choosing option C or D.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Integrals - Class 12 |
| Concept | Definite Integral Properties (King's Property) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |